The nth term of the sequence whose integers are between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹
Consecutive numbers are those numbers that succeed each other in increasing order from least to greatest. The numbers that are given:
Now, suppose a (n) denotes the number of n-digit positive integers as stated in the question, thereby using:
Then, the number of n can be computed as n!
= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)
= 1.254 × 10¹¹
Learn more about consecutive numbers here:
https://brainly.com/question/26352026
The nth term of the series of integers is between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹
Consecutive numbers are those numbers that succeed by each other in increasing order from lowest to greatest such are 1, 2, 3, 4, 5, 6, or 7.
Now, suppose n represents the number of n-digit positive integers.
1, 2, 3, 4, 5, 6, or 7 with the permission of repetition no two consecutive digits are even.
Then, the number of n can be calculated as n!
= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)
= 1.254 × 10¹¹
Learn more about consecutive numbers here:
brainly.com/question/26352026
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