Given two parallel lines and a transversal
The given angles: (2x-8) and (9x-10) are supplementary angles
So, the sum of the angles = 180
So,
[tex](2x-8)+(9x-10)=180[/tex]
Solve the equation to find x :
[tex]\begin{gathered} 2x-8+9x-10=180 \\ 11x-18=180 \\ 11x=180+18 \\ 11x=198 \\ \\ x=\frac{198}{11}=18 \end{gathered}[/tex]
So, the answer will be x = 18
The converse of the solution:
when x = 18
So, the measure of the angles will be:
2x - 8 = 2 * 18 - 8 = 36 - 8 = 28
9x - 10 = 9 * 18 - 10 = 162 - 10 = 152
The sum of the angles are = 28 + 152 = 180
So, the sum of the angles = 180
So, the angles are supplementary angles
So, the lines J and K are parallel lines
so, J || K
